The input specifies there is 1 test case. For the first test case, the size of the array is 6. The array elements are 5 6 1 2 3 4. We use the arrayRotateCheck function to find the rotation index. Iteration 1: 5 > 6 (not true) Iteration 2: 6 > 1 (true) The current index (i) is 1, and i + 1 is 2. So, the rotation index is 2. The function returns 2. The output for the test case is 2. public class Solution { public static int arrayRotateCheck ( int [] arr ){ for ( int i = 0 ; i < arr . length - 1 ; i ++){ if ( arr [ i ] > arr [ i + 1 ]){ return i + 1 ; ...